Arrangement of following compounds based on their boiling points in the increasing order: n-butane, 1-butanol, ethoxyethane and 1-propanol will be

Question

Arrangement of following compounds based on their boiling points in the increasing order: n-butane, 1-butanol, ethoxyethane and 1-propanol will be (A) 1-propanol > n-butane > ethoxyethane > 1-butanol (B) n-butane < ethoxyethane < 1-propanol < 1-butanol (C) n-butane < 1-propanol < ethoxyethane < 1-butanol (D) 1-propanol < n-butane < ethoxyethane < 1-butanol

Tardigrade Admin · Accepted Answer

Boiling point increases with increase in molecular mass so, 1-butanol has higher boiling point than 1-propanol.Unlike alcohols, ethers do not form hydrogen bonds thus, they have lower boiling points than the corresponding alcohols. Due to weak dipole-dipole interactions, the boiling points of lower ethers are only slightly higher than those of the n-alkanes having comparable molecular masses.Thus, the increasing order of boiling points is n-butane < ethoxyethane < 1-propanol < 1-butanol.

Q. Arrangement of following compounds based on their boiling points in the increasing order : $n - b u t an e, 1 - b u t an o l, e t h o x ye t han e an d 1 - p ro p an o l$ will be

$1 - p ro p an o l > n - b u t an e > e t h o x ye t han e > 1 - b u t an o l$

$n - b u t an e < e t h o x ye t han e < 1 - p ro p an o l < 1 - b u t an o l$

$n - b u t an e < 1 - p ro p an o l < e t h o x ye t han e < 1 - b u t an o l$

$1 - p ro p an o l < n - b u t an e < e t h o x ye t han e < 1 - b u t an o l$

Q. Arrangement of following compounds based on their boiling points in the increasing order : n−butane,1−butanol,ethoxyethaneand1−propanol will be

1−propanol>n−butane>ethoxyethane>1−butanol

n−butane<ethoxyethane<1−propanol<1−butanol

n−butane<1−propanol<ethoxyethane<1−butanol

1−propanol<n−butane<ethoxyethane<1−butanol

Q. Arrangement of following compounds based on their boiling points in the increasing order : $n - b u t an e, 1 - b u t an o l, e t h o x ye t han e an d 1 - p ro p an o l$ will be

$1 - p ro p an o l > n - b u t an e > e t h o x ye t han e > 1 - b u t an o l$

$n - b u t an e < e t h o x ye t han e < 1 - p ro p an o l < 1 - b u t an o l$

$n - b u t an e < 1 - p ro p an o l < e t h o x ye t han e < 1 - b u t an o l$

$1 - p ro p an o l < n - b u t an e < e t h o x ye t han e < 1 - b u t an o l$