Arrange the following in increasing oxidation number of iodine: I2, HI, HIO4, ICl

Question

Arrange the following in increasing oxidation number of iodine: I2, HI, HIO4, ICl (A) ICl < I2 < HI < HIO4 (B) I2< HI< HIO4< ICl (C) HI < ICl < I2 < HIO4 (D) HI< I2< ICl< HIO4

Tardigrade Admin · Accepted Answer

Compound I2 HI HIO4 ICl O.S. 0 -1 +7 +1

Q. Arrange the following in increasing oxidation number of iodine: $I_{2}, H I, H I O_{4}, I Cl$

$I Cl < I_{2} < H I < H I O_{4}$

$I_{2} < H I < H I O_{4} < I Cl$

$H I < I Cl < I_{2} < H I O_{4}$

$H I < I_{2} < I Cl < H I O_{4}$

Compound $I_{2}$ $H I$ $H I O_{4}$ $I Cl$

O.S. 0 -1 +7 +1

Q. Arrange the following in increasing oxidation number of iodine: I2​,HI,HIO4​,ICl

ICl<I2​<HI<HIO4​

I2​<HI<HIO4​<ICl

HI<ICl<I2​<HIO4​

HI<I2​<ICl<HIO4​