Arrange He2+, C22-, O2- and NO in increasing order of their bond orders.

Question

Arrange He2+, C22-, O2- and NO in increasing order of their bond orders. (A) NO < O2- < C22- < He2+ (B) O2 < NO < C22- < He2+ (C) C22- < He2+ < O2- < NO (D) He2+ < O2 < NO < C22-

Tardigrade Admin · Accepted Answer

beginaligned beginarray|c|c| hline text Diatomic species text Bond order hline mathrmNO 2.5 hline mathrmO2- 1.5 hline mathrmC22- 3.0 hline mathrmHe2 + 0.5 hline endarray text Thus, increasing order mathrmHe2+< mathrmO2-< mathrmNO< mathrmC22- endaligned

Q. Arrange $H e_{2}^{+}, C_{2}^{2 -}, O_{2}^{-}$ and $NO$ in increasing order of their bond orders.

$NO < O_{2}^{-} < C_{2}^{2 -} < H e_{2}^{+}$

$O_{2} < NO < C_{2}^{2 -} < H e_{2}^{+}$

$C_{2}^{2 -} < H e_{2}^{+} < O_{2}^{-} < NO$

$H e_{2}^{+} < O_{2} < NO < C_{2}^{2 -}$

Q. Arrange He2+​,C22−​,O2−​ and NO in increasing order of their bond orders.

NO<O2−​<C22−​<He2+​

O2​<NO<C22−​<He2+​

C22−​<He2+​<O2−​<NO

He2+​<O2​<NO<C22−​

Q. Arrange $H e_{2}^{+}, C_{2}^{2 -}, O_{2}^{-}$ and $NO$ in increasing order of their bond orders.

$NO < O_{2}^{-} < C_{2}^{2 -} < H e_{2}^{+}$

$O_{2} < NO < C_{2}^{2 -} < H e_{2}^{+}$

$C_{2}^{2 -} < H e_{2}^{+} < O_{2}^{-} < NO$

$H e_{2}^{+} < O_{2} < NO < C_{2}^{2 -}$