Question

Arg z + Arg $\bar{z}.(z\ne 0)$ is

• A. 0
• B. $\pi$
• C. $\frac{\pi }{2}$
• D. none of these

Answer 1

Answer: (C)

Let $z=r{e}^{i\theta }\therefore \bar{z}=r{e}^{-i\theta }]$
$\Rightarrow Arg,z+Arg.\bar{z}=\theta -\theta =0$.
$[\because -\pi <\theta \le \pi$ for $Arg2]$