Area enclosed by the curve y= sin x between x=2 n π to x=2(n+1) π is-

Question

Area enclosed by the curve y= sin x between x=2 n π to x=2(n+1) π is- (A) ∫ limits02 π sin x d x (B) 2 ∫ limits0π sin x d x (C) 4 ∫ limits0π / 2 sin x d x (D) 4

Tardigrade Admin · Accepted Answer

Correct answer is (b) 2 ∫ limits0π sin x d xCorrect answer is (c) 4 ∫ limits0π / 2 sin x d xCorrect answer is (d) 4

Q. Area enclosed by the curve $y = sin x$ between $x = 2 nπ$ to $x = 2 (n + 1) π$ is-

$0 \int 2 π sin x d x$

$2 0 \int π sin x d x$

$4 0 \int π /2 sin x d x$

4

Correct answer is (b) $2 0 \int π sin x d x$ Correct answer is (c) $4 0 \int π /2 sin x d x$ Correct answer is (d) 4

Q. Area enclosed by the curve y=sinx between x=2nπ to x=2(n+1)π is-

0∫2π​sinxdx

20∫π​sinxdx

40∫π/2​sinxdx

4

Correct answer is (b) 20∫π​sinxdx Correct answer is (c) 40∫π/2​sinxdx Correct answer is (d) 4

Q. Area enclosed by the curve $y = sin x$ between $x = 2 nπ$ to $x = 2 (n + 1) π$ is-

$0 \int 2 π sin x d x$

$2 0 \int π sin x d x$

$4 0 \int π /2 sin x d x$

Correct answer is (b) $2 0 \int π sin x d x$ Correct answer is (c) $4 0 \int π /2 sin x d x$ Correct answer is (d) 4