Aqueous sulphite reacts with dilute sulphuric acid to form X(g). The liberated X(g) is oassed into acidified KMnO 4 solution. What s the oxidation state of Mn in the product formed?

Question

Aqueous sulphite reacts with dilute sulphuric acid to form X(g). The liberated X(g) is oassed into acidified KMnO 4 solution. What s the oxidation state of Mn in the product formed? (A) +6 (B) +4 (C) +2 (D) +3

Tardigrade Admin · Accepted Answer

Aqueous sulphite when reacts with sulphuric acid, it gives

S O_{2} (g)

which when react (passed) with acidified

K M n O_{4}

gives

M n^{2 +}

ions as follows:

(i)

S O_{3}^{2 -} + H_{2} S O_{4} ⟶ S O_{4}^{2 -} + S O_{2} + H_{2} O

(ii)

5 S O_{2} + 2 K M n O_{4} + 2 H_{2} O ⟶ K_{2} S O_{4}

+ 2 M n S O_{4} + 2 H_{2} S O_{4}

∵

Oxidation state of

M n

in

M n S O_{4}

is

+ 2

Q. Aqueous sulphite reacts with dilute sulphuric acid to form X(g). The liberated X(g) is oassed into acidified KMnO4​ solution. What s the oxidation state of Mn in the product formed?

+6

+4

+2

+3

Q. Aqueous sulphite reacts with dilute sulphuric acid to form $X (g)$ . The liberated $X (g)$ is oassed into acidified $K M n O_{4}$ solution. What s the oxidation state of $M n$ in the product formed?