Aqueous solution of 0.004 textM Na2SO4 and 0.01 textM glucose are isotonic. The percentage degree of dissociation of Na2SO4 is

Question

Aqueous solution of 0.004 textM Na2SO4 and 0.01 textM glucose are isotonic. The percentage degree of dissociation of Na2SO4 is (A) 85 % (B) 75 % (C) 60 % (D) 25 %

Tardigrade Admin · Accepted Answer

For two solutions to be isotonic. i × π Na 2 SO 4=π text Glucose (1+2 α) C1 R T=C2 R T (1+2 α) × 0.004=0.01 α=0.75 text or 75 %

Q. Aqueous solution of $0.004 M$ $N a_{2} S O_{4}$ and $0.01 M$ glucose are isotonic. The percentage degree of dissociation of $N a_{2} S O_{4}$ is

$85%$

$75%$

$60%$

$25%$

For two solutions to be isotonic.
$i \times π_{N a_{2}} S O_{4} = π_{Glucose}$
$(1 + 2 α) C_{1} RT = C_{2} RT$
$(1 + 2 α) \times 0.004 = 0.01$
$α = 0.75 or 75%$

Q. Aqueous solution of 0.004M Na2​SO4​ and 0.01M glucose are isotonic. The percentage degree of dissociation of Na2​SO4​ is

85%

75%

60%

25%