Question

Analysis shows that an oxide ore of nickel has formula $N{i}_{0.98}{O}_{1.00}$ The percentage of nickel as $N{i}^{3+}$ ions is nearly

• A. 2
• B. 96
• C. 4
• D. 98

Answer 1

Answer: (C)

Let no. of nickel ions $=98$
$\therefore$ No. of oxide ions $=100$
Total negative charge on $O^{2-}$ ions
$=2\times 100=200$
Let no. of $N{i}^{3+}$ ions $=x$
$\therefore$ No. of $N{i}^{2+}$ ions $=98-x$
$x\times 3+(98-x)\times 2=200$
$3x-2x=200-196$
$x=4$
Percentage of nickel as $N{i}^{3+}=\frac{4}{98}\times 100$
$=4.08$