An unsaturated hydrocarbon X on ozonolysis gives A. Compound A when warmed with ammonical silver nitrate forms a bright silver mirror along the sides of the test tube. The unsaturated hydrocarbon X is :

Question

An unsaturated hydrocarbon X on ozonolysis gives A. Compound A when warmed with ammonical silver nitrate forms a bright silver mirror along the sides of the test tube. The unsaturated hydrocarbon X is : (A)  (B)  (C) HC≡ C-CH2-CH3 (D) HC3-C≡ C-CH3

Tardigrade Admin · Accepted Answer

As (A) compound given positive tollen 's test hence it may consist-CHO (aldehyde group). or it can be

H COO H

So for the given option:

(3)

C H_{3} - C H_{2} - C \equiv C H Ozonolysis C H_{3} C H_{2} COO H + + ve tollen’s test (A) H COO H

and for other compounds (options):

(3)

C H_{3} - C \equiv C - C H_{3} Ozonolysis (Does not show tollen’s test) 2 C H_{3} - COO H

(3) CH3 -C ≡ C - CH3 xrightarrow textOzonolysis underset text(Does not show tollen's test)2 CH3 - COOH

Q. An unsaturated hydrocarbon $X$ on ozonolysis gives A. Compound A when warmed with ammonical silver nitrate forms a bright silver mirror along the sides of the test tube. The unsaturated hydrocarbon $X$ is :

$H C \equiv C - C H_{2} - C H_{3}$

$H C_{3} - C \equiv C - C H_{3}$

Q. An unsaturated hydrocarbon X on ozonolysis gives A. Compound A when warmed with ammonical silver nitrate forms a bright silver mirror along the sides of the test tube. The unsaturated hydrocarbon X is :

HC≡C−CH2​−CH3​

HC3​−C≡C−CH3​

Q. An unsaturated hydrocarbon $X$ on ozonolysis gives A. Compound A when warmed with ammonical silver nitrate forms a bright silver mirror along the sides of the test tube. The unsaturated hydrocarbon $X$ is :

$H C \equiv C - C H_{2} - C H_{3}$

$H C_{3} - C \equiv C - C H_{3}$