Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
An unsaturated hydrocarbon upon ozonolysis gives one mole each of formaldehyde, acetaldehyde and methyl glyoxal (CH3COCHO). The structure of the hydrocarbon is
Q. An unsaturated hydrocarbon upon ozonolysis gives one mole each of formaldehyde, acetaldehyde and methyl glyoxal
(
C
H
3
COC
H
O
). The structure of the hydrocarbon is
3418
199
Hydrocarbons
Report Error
A
C
H
2
=
C
H
−
C
H
2
−
C
H
=
C
H
2
5%
B
C
H
2
=
C
H
−
C
(
C
H
3
)
=
C
H
−
C
H
3
88%
C
(
C
H
3
)
2
C
=
C
H
−
C
H
3
3%
D
C
H
3
−
C
H
=
C
(
C
H
3
)
−
C
H
3
3%
Solution: