An underwater swimmer is at a depth of 12 m below the surface of water. A bird is at a height of 18 m from the surface of water, directly above his eyes. For the swimmer the bird appears to be at a distance of .....from the surface of water. (Refractive index of water is 4/3):

Question

An underwater swimmer is at a depth of 12 m below the surface of water. A bird is at a height of 18 m from the surface of water, directly above his eyes. For the swimmer the bird appears to be at a distance of .....from the surface of water. (Refractive index of water is 4/3): (A) 24 m (B) 12 m (C) 18 m (D) 9 m

Tardigrade Admin · Accepted Answer

gμ a=(actual text depth/apparent text depth) Apparent depth =(18/(3)4)=(18× 4/3)=24 m

Q. An underwater swimmer is at a depth of 12 m below the surface of water. A bird is at a height of 18 m from the surface of water, directly above his eyes. For the swimmer the bird appears to be at a distance of .....from the surface of water. (Refractive index of water is 4/3):

24 m

12 m

18 m

9 m

16m

$_{g} μ_{a} = \frac{a c t u a l d e pt h}{a pp a re n t d e pt h}$
Apparent depth $= \frac{18}{\frac{3}{4}} = \frac{18 \times 4}{3} = 24 m$

Q. An underwater swimmer is at a depth of 12 m below the surface of water. A bird is at a height of 18 m from the surface of water, directly above his eyes. For the swimmer the bird appears to be at a distance of .....from the surface of water. (Refractive index of water is 4/3):

24 m

12 m

18 m

9 m

16m

g​μa​=apparentdepthactualdepth​ Apparent depth =43​18​=318×4​=24m

$_{g} μ_{a} = \frac{a c t u a l d e pt h}{a pp a re n t d e pt h}$
Apparent depth $= \frac{18}{\frac{3}{4}} = \frac{18 \times 4}{3} = 24 m$