Question

An oxide of iodine (atomic mass = $127$) contains $25.4g$ of iodine and $8g$ of oxygen. Its formula would be

• A. $I_2{O}_3$
• B. $I_{2}O$
• C. $I_2{O}_5$
• D. $I_2{O}_7$

Answer 1

Answer: (C)

$25.4g{I}_2$ combines with $8g$ of oxygen.
$\therefore 254g$ iodine will combine with $80g$ of oxygen.
$\therefore$ Formula of oxide of iodine would be $I_2{O}_5$.
$\frac{80}{16}=5$ and $\frac{254}{2}=127$