An organic compound has an empirical formula CH2O, its vapour density is 45. The molecular formula of the compound is:

Question

An organic compound has an empirical formula CH2O, its vapour density is 45. The molecular formula of the compound is: (A)  CH2O  (B)  C2H5O  (C)  C2H2O  (D)  C3H6O3

Tardigrade Admin · Accepted Answer

Mol. wt = 2 × vap. density =2 × 45=90 Empirical formula weight =12+2+16=30 ∴ n=( text mol. wt. / text empirical formula wt. ) = (90/30)=3 ∴ Molecular formula of the compound =( CH 2 O )3 = C 3 H 6 O 3

Q. An organic compound has an empirical formula $C H_{2} O,$ its vapour density is $45$ . The molecular formula of the compound is:

$C H_{2} O$

$C_{2} H_{5} O$

$C_{2} H_{2} O$

$C_{3} H_{6} O_{3}$

Mol. wt $= 2 \times$ vap. density
$= 2 \times 45 = 90$
Empirical formula weight
$= 12 + 2 + 16 = 30$
$∴ n = \frac{mol. wt.}{empirical formula wt.}$
$= \frac{90}{30} = 3$
$∴$ Molecular formula of the compound
$= (C H_{2} O)_{3}$
$= C_{3} H_{6} O_{3}$

Q. An organic compound has an empirical formula CH2​O, its vapour density is 45. The molecular formula of the compound is:

CH2​O

C2​H5​O

C2​H2​O

C3​H6​O3​