An organic compound contains 40 %C, 6.66 % H and rest oxygen. Its vapour density is 30. What will be its empirical formula?

Question

An organic compound contains 40 %C, 6.66 % H and rest oxygen. Its vapour density is 30. What will be its empirical formula? (A) CHO (B) CH2 O (C) C2 H2 O (D) CH4 O

Tardigrade Admin · Accepted Answer

Calculation of empirical formula:

Element	Percentage	At. mass	Relative number of atoms	Simplest ratio
Carbon	$40.0$	$12$	$\frac{40}{10} = 3.33$	$\frac{3.33}{3.33} = 1$
Hydro gen	$6.66$	$1$	$\frac{6.66}{1} = 6.66$	$\frac{6.66}{3.33} = 2$
Oxygen	$53.34$ (by difference)	$16$	$\frac{53.34}{16} = 3.33$	$\frac{3.33}{3.33} = 1$

Empirical formula -

C H_{2} O

Q. An organic compound contains $40% C, 6.66% H$ and rest oxygen. Its vapour density is $30$ . What will be its empirical formula?

$C H O$

$C H_{2} O$

$C_{2} H_{2} O$

$C H_{4} O$

Q. An organic compound contains 40%C,6.66%H and rest oxygen. Its vapour density is 30. What will be its empirical formula?

CHO

CH2​O

C2​H2​O

CH4​O

Calculation of empirical formula: Element Percentage At. mass Relative number of atoms Simplest ratio Carbon 40.0 12 1040​=3.33 3.333.33​=1 Hydro gen 6.66 1 16.66​=6.66 3.336.66​=2 Oxygen 53.34 (by difference) 16 1653.34​=3.33 3.333.33​=1 Empirical formula - CH2​O

Q. An organic compound contains $40% C, 6.66% H$ and rest oxygen. Its vapour density is $30$ . What will be its empirical formula?

$C H O$

$C H_{2} O$

$C_{2} H_{2} O$

$C H_{4} O$