An open vessel at 300 K is heated till 2/5th of the air in it is expelled. Assuming that the volume of the vessel remains constant, the temperature to which the vessel is heated, is

Question

An open vessel at 300 K is heated till 2/5th of the air in it is expelled. Assuming that the volume of the vessel remains constant, the temperature to which the vessel is heated, is (A) 1500 K (B) 400 K (C) 500 K (D) 750 K

Tardigrade Admin · Accepted Answer

We know at constant V and P: n 1 T 1= n 2 T 2 [∵ P1 V1. constant ] n 1= n and n 2= n -(2 n /5) and T 1=300 K n (300)=( n -(2/5) n )( T 2)=((3 n /5)) T 2 T 2=500 K

Q. An open vessel at $300 K$ is heated till $2/ 5^{t h}$ of the air in it is expelled. Assuming that the volume of the vessel remains constant, the temperature to which the vessel is heated, is

$1500 K$

$400 K$

$500 K$

$750 K$

We know at constant $V$ and $P$ :
$n_{1} T_{1} = n_{2} T_{2}$
$[∵ P_{1} V_{1}$ constant $]$
$n_{1} = n$ and $n_{2} = n - \frac{2 n}{5}$ and $T_{1} = 300 K$
$n (300) = (n - \frac{2}{5} n) (T_{2}) = (\frac{3 n}{5}) T_{2}$
$T_{2} = 500 K$

Q. An open vessel at 300K is heated till 2/5th of the air in it is expelled. Assuming that the volume of the vessel remains constant, the temperature to which the vessel is heated, is

1500K

400K

500K

750K