An object is projected from ground with speed 20 m / s at angle 30° with horizontal. Its centripetal acceleration one second after the projection is [Take g=10 m / s 2 ]

Question

An object is projected from ground with speed 20 m / s at angle 30° with horizontal. Its centripetal acceleration one second after the projection is [Take g=10 m / s 2 ] (A) 10 m / s 2 (B) Zero (C) 5 m / s 2 (D) 12 m / s 2

Tardigrade Admin · Accepted Answer

Centripetal acceleration =(v2/r)=g-10 m s2

Q. An object is projected from ground with speed $20 m / s$ at angle $3 0^{\circ}$ with horizontal. Its centripetal acceleration one second after the projection is [Take $g = 10 m / s^{2}$ ]

$10 m / s^{2}$

Zero

$5 m / s^{2}$

$12 m / s^{2}$

Centripetal acceleration $= \frac{v ^{2}}{r} = g - 10 m s^{2}$

Q. An object is projected from ground with speed 20m/s at angle 30∘ with horizontal. Its centripetal acceleration one second after the projection is [Take g=10m/s2 ]

10m/s2

Zero

5m/s2

12m/s2

Centripetal acceleration =rv2​=g−10ms2

Q. An object is projected from ground with speed $20 m / s$ at angle $3 0^{\circ}$ with horizontal. Its centripetal acceleration one second after the projection is [Take $g = 10 m / s^{2}$ ]

$10 m / s^{2}$

$5 m / s^{2}$

$12 m / s^{2}$

Centripetal acceleration $= \frac{v ^{2}}{r} = g - 10 m s^{2}$