Question

An object accelerates from rest to a velocity $27.5m/s$ in $10s$ , then the distance covered after next $10s$ is:

• A. 550 m
• B. 137.5 m
• C. 412.5 m
• D. 175 m

Answer 1

Answer: (C)

Since, the object accelerates from rest, its initial velocity $(u)$ is zero.
That is, $u=0$ From first equation of motion
$v=u+at$
$\therefore 27.5=0+a\times 10$
or $a=2.75m/s^2$
Hence, distance covered in first $10s$
$s_1=ut+\frac{1}{2}a{t}^2$
$=0+\frac{1}{2}\times 2.75\times (10{)}^2$
$=137.5m$
Distance covered in next $10s$ with uniform velocity of $27.5m/s$
$s_2=27.5\times 10=275m$
Total distance covered
$s=137.5+275=412.5m$