An ideal gas undergoes a reversible isothermal expansion from a state i to f . The change in entropy Δ S (i→ f) ) is

Question

An ideal gas undergoes a reversible isothermal expansion from a state i to f . The change in entropy Δ S (i→ f) ) is (A) 0 (B) > 0 (C) < 0 (D) not defined for the process

Tardigrade Admin · Accepted Answer

Change in entropy d S=(d Q/T) Entropy remains constant for reversible process d S=0

Q. An ideal gas undergoes a reversible isothermal expansion from a state $i$ to $f$ . The change in entropy $Δ S (i \to f)$ ) is

0

> 0

< 0

not defined for the process

Change in entropy $d S = \frac{d Q}{T}$ Entropy remains constant for reversible process $d S = 0$

Q. An ideal gas undergoes a reversible isothermal expansion from a state i to f . The change in entropy ΔS(i→f) ) is

0

> 0

< 0

not defined for the process

Change in entropy dS=TdQ​ Entropy remains constant for reversible process dS=0

Q. An ideal gas undergoes a reversible isothermal expansion from a state $i$ to $f$ . The change in entropy $Δ S (i \to f)$ ) is

Change in entropy $d S = \frac{d Q}{T}$ Entropy remains constant for reversible process $d S = 0$