An iceberg is floating in ocean. What fraction of its volume is above the water? (Given: density of ice =900 kg / m 3 and density of ocean water =1030 kg / m 3 )

Question

An iceberg is floating in ocean. What fraction of its volume is above the water? (Given: density of ice =900 kg / m 3 and density of ocean water =1030 kg / m 3 ) (A) (90/103) (B) (13/103) (C) (10/103) (D) (1/103)

Tardigrade Admin · Accepted Answer

Let V be the volume of iceberg and let x be the fraction of volume above water. Using law of floatation, weight of floating body = weight of liquid displaced by part of the floating body inside the liquid. Therefore, V ρ text ice g=(1-x) V ρ text water g. Using the value of ρ text ice and ρ text water we get x=(13 / 103).

Q. An iceberg is floating in ocean. What fraction of its volume is above the water? (Given : density of ice $= 900 k g / m^{3}$ and density of ocean water $= 1030 k g / m^{3}$ )

$\frac{90}{103}$

$\frac{13}{103}$

$\frac{10}{103}$

$\frac{1}{103}$

Q. An iceberg is floating in ocean. What fraction of its volume is above the water? (Given : density of ice =900kg/m3 and density of ocean water =1030kg/m3 )

10390​

10313​

10310​

1031​

Q. An iceberg is floating in ocean. What fraction of its volume is above the water? (Given : density of ice $= 900 k g / m^{3}$ and density of ocean water $= 1030 k g / m^{3}$ )

$\frac{90}{103}$

$\frac{13}{103}$

$\frac{10}{103}$

$\frac{1}{103}$