Q.
An ellipse has foci (4,2),(2,2) and it passes through the point P(2,4) . The eccentricity of the ellipse is
2810
213
NTA AbhyasNTA Abhyas 2020Conic Sections
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Solution:
Let, (4,2)=S1​ and (2,2)=S2​ and eccentricity of ellipse is e
then S1​S2​=2ae and PS1​+PS2​=2a
(where 2a is length of major axis) ⇒e=PS1​+PS2​S1​S2​​=22​+22​ ⇒e=2​+11​=2​−1=tan8π​