Question

An elevator in a building can carry a maximum of $10$ persons with the average mass of each person being $68kg$. The mass of the elevator itself is $920kg$ and it moves with a constant speed of $3m/s$. The frictional force opposing the motion is $6000N$. If the elevator is moving up with its full capacity, the power delivered by the motor to the elevator $\left(g=10m/s^2\right)$ must be at least

• A. 62360 W
• B. 48000 W
• C. 56300 W
• D. 66000 W

Answer 1

Answer: (D)

Mass of elevator, $M=920kg$
Mass of all ' $10$ ' passengers carried by elevator $=10\times m$
$=10\times 68=680kg$
Total weight of elevator and passengers
$=(M+10m)g=(920+680)\times 10=16000N$

Force of friction $=6000N$
Total force $(T)$ applied by the motor of elevator
$=16000+6000=22000N$
Power delivered by elevator's motor,
$P=F\cdot v=22000\times 3$
$\left[\because v=3m{s}^{-1}\right]$
$=66000W$