Question

An element ${}^{\prime }{P}^{\prime }$ has atomic number $56$. What will be the formula of its halide?

• A. $PX$
• B. $P{X}_2$
• C. $P{X}_3$
• D. $P_2{X}_3$

Answer 1

Answer: (B)

$Z=56$; $[Xe]6s^2$
Formula of halide is $P{X}_2$.