An electron revolving in an orbit of radius 0.5 A in a hydrogen atom executes 1016rev/s . The magnetic moment of electron due to its orbital motion will be,

Question

An electron revolving in an orbit of radius 0.5 A in a hydrogen atom executes 1016rev/s . The magnetic moment of electron due to its orbital motion will be, (A)  1256× 10-26Am2  (B)  6.53× 10-26Am2  (C) zero (D)  256× 10-26Am2

Tardigrade Admin · Accepted Answer

M=I text A=(ev) text π r2 =1.6× 10-19× 1016× (22/7)× (0.5× 10-10)2 =1256× 10-26 Am2

Q. An electron revolving in an orbit of radius 0.5 A in a hydrogen atom executes $10^{16} re v / s$ . The magnetic moment of electron due to its orbital motion will be,

$1256 \times 10^{- 26} A m^{2}$

$6.53 \times 10^{- 26} A m^{2}$

zero

$256 \times 10^{- 26} A m^{2}$

$M = I A = (e v) π r^{2}$ $= 1.6 \times 10^{- 19} \times 10^{16} \times \frac{22}{7} \times (0.5 \times 10^{- 10})^{2}$ $= 1256 \times 10^{- 26} A m^{2}$

Q. An electron revolving in an orbit of radius 0.5 A in a hydrogen atom executes 1016rev/s . The magnetic moment of electron due to its orbital motion will be,

1256×10−26Am2

6.53×10−26Am2