An electron of mass m and a photon have same energy E. The ratio of wavelength of electron to that of photon is: (c being the velocity of light)

Question

An electron of mass m and a photon have same energy E. The ratio of wavelength of electron to that of photon is: (c being the velocity of light) (A) (1/c)((2 m/E))1 / 2 (B) (1/c)((E/2 m))1 / 2 (C) (( E /2 m ))1 / 2 (D) c (2 mE )1 / 2

Tardigrade Admin · Accepted Answer

λ1=( h /√2 mE ) λ2=( hc / E ) (λ1/λ2)=(1/ c )(( E /2 m ))1 / 2

Q. An electron of mass $m$ and a photon have same energy $E$ . The ratio of wavelength of electron to that of photon is : ( $c$ being the velocity of light)

$\frac{1}{c} (\frac{2 m}{E})^{1/2}$

$\frac{1}{c} (\frac{E}{2 m})^{1/2}$

$(\frac{E}{2 m})^{1/2}$

$c (2 m E)^{1/2}$

$λ_{1} = \frac{h}{2 m E}$
$λ_{2} = \frac{h c}{E}$
$\frac{λ _{1}}{λ _{2}} = \frac{1}{c} (\frac{E}{2 m})^{1/2}$

Q. An electron of mass m and a photon have same energy E. The ratio of wavelength of electron to that of photon is : (c being the velocity of light)

c1​(E2m​)1/2

c1​(2mE​)1/2

(2mE​)1/2

c(2mE)1/2