An electron moving in a circular orbit of radius r makes n rotations per second. The magnetic field produced at the centre has magnitude

Question

An electron moving in a circular orbit of radius r makes n rotations per second. The magnetic field produced at the centre has magnitude (A) (μ0 n2 e/r) (B) (μ0 n e/2r) (C) (μ0 n e/2 π r) (D) Zero

Tardigrade Admin · Accepted Answer

Current in the orbit, I=(e/T) I=(e/(2 π/ω))=(ω e/2 π)=((2 π n)e/2 π)=ne Magnetic field at centre of current carrying circular coil is given by B=(μ0 I/2r)=(μ0 ne/2r)

Q. An electron moving in a circular orbit of radius r makes n rotations per second. The magnetic field produced at the centre has magnitude

$\frac{μ _{0} n ^{2} e}{r}$

$\frac{μ _{0} n e}{2 r}$

$\frac{μ _{0} n e}{2 π r}$

Zero

Current in the orbit, $I = \frac{e}{T}$
$I = \frac{e}{( 2 π / ω )} = \frac{ω e}{2 π} = \frac{( 2 πn ) e}{2 π} = n e$
Magnetic field at centre of current carrying circular
coil is given by
$B = \frac{μ _{0} I}{2 r} = \frac{μ _{0} n e}{2 r}$

Q. An electron moving in a circular orbit of radius r makes n rotations per second. The magnetic field produced at the centre has magnitude

rμ0​n2e​

2rμ0​ne​

2πrμ0​ne​

Zero

Current in the orbit, I=Te​ I=(2π/ω)e​=2πωe​=2π(2πn)e​=ne Magnetic field at centre of current carrying circular coil is given by B=2rμ0​I​=2rμ0​ne​

$\frac{μ _{0} n ^{2} e}{r}$

$\frac{μ _{0} n e}{2 r}$

$\frac{μ _{0} n e}{2 π r}$

Current in the orbit, $I = \frac{e}{T}$
$I = \frac{e}{( 2 π / ω )} = \frac{ω e}{2 π} = \frac{( 2 πn ) e}{2 π} = n e$
Magnetic field at centre of current carrying circular
coil is given by
$B = \frac{μ _{0} I}{2 r} = \frac{μ _{0} n e}{2 r}$