An electron moves in a circle of radius 1.0 cm with a constant speed of 4.0× 106m/s , the electric current at a point on the circle will be (e=1.6× 10-19C)

Question

An electron moves in a circle of radius 1.0 cm with a constant speed of 4.0× 106m/s , the electric current at a point on the circle will be (e=1.6× 10-19C)  (A)  1× 10-11Ω  (B)  1.1× 10-7Ω  (C)  5.1× 10-7Ω  (D)  2.1× 10-7Ω

Tardigrade Admin · Accepted Answer

Using the releation i=(q/t)=(electronic text charge/time text period)=(e/t) Hence, t=(2π r/v) So, i=(e/2π rv) =(ev/2π r) =((1.6× 10-19)(4× 106)/2× 3.14× 1.0× 10-2) =1× 10-11Ω

Q. An electron moves in a circle of radius $1.0 c m$ with a constant speed of $4.0 \times 10^{6} m / s$ , the electric current at a point on the circle will be $(e = 1.6 \times 10^{- 19} C)$

$1 \times 10^{- 11} Ω$

$1.1 \times 10^{- 7} Ω$

$5.1 \times 10^{- 7} Ω$

$2.1 \times 10^{- 7} Ω$

Q. An electron moves in a circle of radius 1.0cm with a constant speed of 4.0×106m/s , the electric current at a point on the circle will be (e=1.6×10−19C)

1×10−11Ω

1.1×10−7Ω

5.1×10−7Ω

2.1×10−7Ω

Using the releation i=tq​=timeperiodelectroniccharge​=te​ Hence, t=v2πr​ So, i=2πrve​ =2πrev​ =2×3.14×1.0×10−2(1.6×10−19)(4×106)​ =1×10−11Ω

Q. An electron moves in a circle of radius $1.0 c m$ with a constant speed of $4.0 \times 10^{6} m / s$ , the electric current at a point on the circle will be $(e = 1.6 \times 10^{- 19} C)$

$1 \times 10^{- 11} Ω$

$1.1 \times 10^{- 7} Ω$

$5.1 \times 10^{- 7} Ω$

$2.1 \times 10^{- 7} Ω$