An electron having charge e and mass m starts from the lower plate of two metallic plates separated by a distance d. If the potential difference between the plates is V, the time taken by the electron to reach the upper plate is given by

Question

An electron having charge e and mass m starts from the lower plate of two metallic plates separated by a distance d. If the potential difference between the plates is V, the time taken by the electron to reach the upper plate is given by (A) √(2 m d2/e V) (B) √(m d2/e V) (C) √(m d2/2 e V) (D) (2 m d2/e V)

Tardigrade Admin · Accepted Answer

E=(V/d), F=e E=e V / d a=(F/m)=(e V/m d) d=(1/2) a t2 or t=√(2 d/a) or t=√(2 d m d/e V)=√(2 m d2/e V)

Q. An electron having charge $e$ and mass $m$ starts from the lower plate of two metallic plates separated by a distance $d$ . If the potential difference between the plates is $V$ , the time taken by the electron to reach the upper plate is given by

$\frac{2 m d ^{2}}{e V}$

$\frac{m d ^{2}}{e V}$

$\frac{m d ^{2}}{2 e V}$

$\frac{2 m d ^{2}}{e V}$

$E = \frac{V}{d}, F = e E = e V / d$
$a = \frac{F}{m} = \frac{e V}{m d}$
$d = \frac{1}{2} a t^{2}$ or $t = \frac{2 d}{a}$
or $t = \frac{2 d m d}{e V} = \frac{2 m d ^{2}}{e V}$

Q. An electron having charge e and mass m starts from the lower plate of two metallic plates separated by a distance d. If the potential difference between the plates is V, the time taken by the electron to reach the upper plate is given by

eV2md2​​

eVmd2​​

2eVmd2​​

eV2md2​

E=dV​,F=eE=eV/d a=mF​=mdeV​ d=21​at2 or t=a2d​​ or t=eV2dmd​​=eV2md2​​

Q. An electron having charge $e$ and mass $m$ starts from the lower plate of two metallic plates separated by a distance $d$ . If the potential difference between the plates is $V$ , the time taken by the electron to reach the upper plate is given by

$\frac{2 m d ^{2}}{e V}$

$\frac{m d ^{2}}{e V}$

$\frac{m d ^{2}}{2 e V}$

$\frac{2 m d ^{2}}{e V}$

$E = \frac{V}{d}, F = e E = e V / d$
$a = \frac{F}{m} = \frac{e V}{m d}$
$d = \frac{1}{2} a t^{2}$ or $t = \frac{2 d}{a}$
or $t = \frac{2 d m d}{e V} = \frac{2 m d ^{2}}{e V}$