An electron has kinetic energy of 2.14 × 10-22J Its de-Broglie wavelength will be nearly (me = 9.1 × 10-31 kg)

Question

An electron has kinetic energy of 2.14 × 10-22J Its de-Broglie wavelength will be nearly (me = 9.1 × 10-31 kg) (A) 9.28 × 10-4 m (B) 9.28 × 10-7 m (C) 9.28 × 10-8 m (D) 9.28 × 10-10 m

Tardigrade Admin · Accepted Answer

E = (hc/λ) or λ = (hc/E) = (6.62× 10-34 × 3 × 108/2.14 × 10-22) = 9.28× 10-8 m.

Q. An electron has kinetic energy of $2.14 \times 1 0^{- 22} J$ Its de-Broglie wavelength will be nearly $(m_{e} = 9.1 \times 1 0^{- 31}$ kg)

$9.28 \times 1 0^{- 4} m$

$9.28 \times 1 0^{- 7} m$

$9.28 \times 1 0^{- 8} m$

$9.28 \times 1 0^{- 10} m$

$E = \frac{h c}{λ}$
or $λ = \frac{h c}{E}$
$= \frac{6.62 \times 1 0 ^{- 34} \times 3 \times 1 0 ^{8}}{2.14 \times 1 0 ^{- 22}}$
$= 9.28 \times 1 0^{- 8} m$ .

Q. An electron has kinetic energy of 2.14×10−22J Its de-Broglie wavelength will be nearly (me​=9.1×10−31 kg)

9.28×10−4m

9.28×10−7m

9.28×10−8m

9.28×10−10m