An electron changes its position from orbitn = 2 to the orbit n = 4 of an atom. The wavelength of the emitted radiations is (R = R vdbergs constant)

Question

An electron changes its position from orbitn = 2 to the orbit n = 4 of an atom. The wavelength of the emitted radiations is (R = R vdbergs constant) (A)  μ  (B)  (1/2)mv2=μ mgs  (C)  (1/2)mv2=(1/2)× 10× (10)2=500kg.m/s.  (D)  v=10m/s,μ =0.5, m=10kg, g=10m/s2

Tardigrade Admin · Accepted Answer

Wavelength of lines emitted is (1/λ )=R( (1/n12)-(1/n22) ) where R Rydbergs constant. Given, n1=2, n2=4 ∴ (1/λ )=R( (1/22)-(1/42) )=(3R/16) ⇒ λ =(16/3R)

Q. An electron changes its position from orbitn = 2 to the orbit n = 4 of an atom. The wavelength of the emitted radiations is (R = R vdbergs constant)

$μ$

$\frac{1}{2} m v^{2} = μ m g s$

$\frac{1}{2} m v^{2} = \frac{1}{2} \times 10 \times (10)^{2} = 500 k g . m / s .$

$v = 10 m / s, μ = 0.5, m = 10 k g, g = 10 m / s^{2}$

Wavelength of lines emitted is $\frac{1}{λ} = R (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}})$ where R Rydbergs constant.
Given, $n_{1} = 2, n_{2} = 4$ $∴$ $\frac{1}{λ} = R (\frac{1}{2 ^{2}} - \frac{1}{4 ^{2}}) = \frac{3 R}{16}$ $\Rightarrow$ $λ = \frac{16}{3 R}$

Q. An electron changes its position from orbitn = 2 to the orbit n = 4 of an atom. The wavelength of the emitted radiations is (R = R vdbergs constant)

μ

21​mv2=μmgs

21​mv2=21​×10×(10)2=500kg.m/s.

v=10m/s,μ=0.5,m=10kg,g=10m/s2

Wavelength of lines emitted is λ1​=R(n12​1​−n22​1​) where R Rydbergs constant.Given, n1​=2,n2​=4 ∴ λ1​=R(221​−421​)=163R​ ⇒ λ=3R16​

$μ$

$\frac{1}{2} m v^{2} = μ m g s$

$\frac{1}{2} m v^{2} = \frac{1}{2} \times 10 \times (10)^{2} = 500 k g . m / s .$

$v = 10 m / s, μ = 0.5, m = 10 k g, g = 10 m / s^{2}$

Wavelength of lines emitted is $\frac{1}{λ} = R (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}})$ where R Rydbergs constant.
Given, $n_{1} = 2, n_{2} = 4$ $∴$ $\frac{1}{λ} = R (\frac{1}{2 ^{2}} - \frac{1}{4 ^{2}}) = \frac{3 R}{16}$ $\Rightarrow$ $λ = \frac{16}{3 R}$