An electrical bulb rated 220 V , 100 W, is connected in series with another bulb rated 220 V , 60 W. If the voltage across combination is 220 V, the power consumed by the 100 W bulb will be about ......W.

Question

An electrical bulb rated 220 V , 100 W, is connected in series with another bulb rated 220 V , 60 W. If the voltage across combination is 220 V, the power consumed by the 100 W bulb will be about ......W. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

R 1=( V 2/ P )=(2202/100)=484 R 2=( V 2/ P )=(2202/60)=484((10/6)) I =(220/484+484 × (10)6) P 1= I 2 R 1=14.06 W

Q. An electrical bulb rated $220 V, 100 W$ , is connected in series with another bulb rated $220 V, 60 W$ . If the voltage across combination is $220 V$ , the power consumed by the $100 W$ bulb will be about ...... $W$ .

$R_{1} = \frac{V ^{2}}{P} = \frac{22 0 ^{2}}{100} = 484$
$R_{2} = \frac{V ^{2}}{P} = \frac{22 0 ^{2}}{60} = 484 (\frac{10}{6})$
$I = \frac{220}{484 + 484 \times \frac{10}{6}}$
$P_{1} = I^{2} R_{1} = 14.06 W$

Q. An electrical bulb rated 220V,100W, is connected in series with another bulb rated 220V,60W. If the voltage across combination is 220V, the power consumed by the 100W bulb will be about ......W.

R1​=PV2​=1002202​=484 R2​=PV2​=602202​=484(610​) I=484+484×610​220​ P1​=I2R1​=14.06W

Q. An electrical bulb rated $220 V, 100 W$ , is connected in series with another bulb rated $220 V, 60 W$ . If the voltage across combination is $220 V$ , the power consumed by the $100 W$ bulb will be about ...... $W$ .

$R_{1} = \frac{V ^{2}}{P} = \frac{22 0 ^{2}}{100} = 484$
$R_{2} = \frac{V ^{2}}{P} = \frac{22 0 ^{2}}{60} = 484 (\frac{10}{6})$
$I = \frac{220}{484 + 484 \times \frac{10}{6}}$
$P_{1} = I^{2} R_{1} = 14.06 W$