An average induced e.m.f. of 1 V appears in a coil when the current in it is changed from 10 A in one direction to 10 A in opposite direction in 0.5 s. Self-inductance of the coil is

Question

An average induced e.m.f. of 1 V appears in a coil when the current in it is changed from 10 A in one direction to 10 A in opposite direction in 0.5 s. Self-inductance of the coil is (A) 25 mH (B) 50 mH (C) 75 mH (D) 100 mH

Tardigrade Admin · Accepted Answer

|e|=L (d i/d t) ⇒ 1=(L × 10-(-10) /0.5) ⇒ L=25 mH

Q. An average induced e.m.f. of $1 V$ appears in a coil when the current in it is changed from $10 A$ in one direction to $10 A$ in opposite direction in $0.5 s$ . Self-inductance of the coil is

25 mH

50 mH

75 mH

100 mH

$∣ e ∣ = L \frac{d i}{d t} \Rightarrow 1 = \frac{L \times { 10 - ( - 10 )}}{0.5}$
$\Rightarrow L = 25 m H$

Q. An average induced e.m.f. of 1V appears in a coil when the current in it is changed from 10A in one direction to 10A in opposite direction in 0.5s. Self-inductance of the coil is