An arrangement of source charges produces electric potential V=5000 x2 along the x-axis, where V is in volt and x is in metre. If a charge particle of mass 1 g and charge 1 nC is present in this field and its turning points are at ± 8.0 cm, then what is the particle's maximum speed (in mm / s ).

Question

An arrangement of source charges produces electric potential V=5000 x2 along the x-axis, where V is in volt and x is in metre. If a charge particle of mass 1 g and charge 1 nC is present in this field and its turning points are at ± 8.0 cm, then what is the particle's maximum speed (in mm / s ). (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

q V=(1/2) m v2 10-9 ×(82-02) × 5000 =(1/2) × 10-3 × v2 v2=64 × 10-6 ⇒ v=8 mm / s

Q. An arrangement of source charges produces electric potential V=5000x2 along the x-axis, where V is in volt and x is in metre. If a charge particle of mass 1g and charge 1nC is present in this field and its turning points are at ±8.0cm, then what is the particle's maximum speed (in mm/s ).

qV=21​mv2 10−9×(82−02)×5000 =21​×10−3×v2 v2=64×10−6 ⇒v=8mm/s

$q V = \frac{1}{2} m v^{2}$
$1 0^{- 9} \times (8^{2} - 0^{2}) \times 5000$
$= \frac{1}{2} \times 1 0^{- 3} \times v^{2}$
$v^{2} = 64 \times 1 0^{- 6}$
$\Rightarrow v = 8 mm / s$