An aqueous solution of a salt MX2 at certain temperature has a van’t Hoff factor of 2. The degree of dissociation for this solution of the salt is :

Question

An aqueous solution of a salt MX2 at certain temperature has a van’t Hoff factor of 2. The degree of dissociation for this solution of the salt is : (A) 0.33 (B) 0.50 (C) 0.67 (D) 0.80

Tardigrade Admin · Accepted Answer

α = (i - 1/k-1) = (2-1/3-1)=(1/2) = 50 %

Q. An aqueous solution of a salt $M X_{2}$ at certain temperature has a van’t Hoff factor of 2. The degree of dissociation for this solution of the salt is :

0.33

0.50

0.67

0.80

$α = \frac{i - 1}{k - 1}$
$= \frac{2 - 1}{3 - 1} = \frac{1}{2} = 50%$

Q. An aqueous solution of a salt MX2​ at certain temperature has a van’t Hoff factor of 2. The degree of dissociation for this solution of the salt is :