An aqueous solution of 6.3 g oxalic acid dehydrate is made upto 250 mL. The volume of 0.1N NaOH required to completely neutralize 10 ml. of this solution is

Question

An aqueous solution of 6.3 g oxalic acid dehydrate is made upto 250 mL. The volume of 0.1N NaOH required to completely neutralize 10 ml. of this solution is (A) 40 mL (B) 20 mL (C) 10 mL (D) 4 mL

Tardigrade Admin · Accepted Answer

Oxalic acid dihydrate H2C2O4 ⋅ 2H2O:mw=126 It is a dibasic acid, hence equivalent weight = 63 ⇒ Normality =(6.3/63)× (1000/250)=0.4 N ⇒ N1V1 =N2V2 ⇒ 0.1 × V1 =0.4 × 10 Hence, V1 =40 mL

Q. An aqueous solution of 6.3g oxalic acid dehydrate is made upto 250mL. The volume of 0.1NNaOH required to completely neutralize 10ml. of this solution is

40 mL

20 mL

10 mL

4 mL

Oxalic acid dihydrate H2​C2​O4​⋅2H2​O:mw=126 It is a dibasic acid, hence equivalent weight = 63 ⇒ Normality =636.3​×2501000​=0.4N ⇒N1​V1​=N2​V2​ ⇒0.1×V1​=0.4×10 Hence, V1​=40mL

Q. An aqueous solution of $6.3 g$ oxalic acid dehydrate is made upto $250 m L$ . The volume of $0.1 N N a O H$ required to completely neutralize $10 m l$ . of this solution is