An alternating current having peak value 14 A used to heat a metal wire. To produce the same heating effect, a constant current i can be used where i is

Question

An alternating current having peak value 14 A used to heat a metal wire. To produce the same heating effect, a constant current i can be used where i is (A) 14 A (B) 20 A (C) 7 A (D) 10 A

Tardigrade Admin · Accepted Answer

I rms =(I0/√2)=(14 A /√2) ≈ 10 A

Q. An alternating current having peak value $14 A$ used to heat a metal wire. To produce the same heating effect, a constant current $i$ can be used where $i$ is

14 A

20 A

7 A

10 A

$I_{r m s} = \frac{I _{0}}{2} = \frac{14 A}{2} \approx 10 A$

Q. An alternating current having peak value 14A used to heat a metal wire. To produce the same heating effect, a constant current i can be used where i is

14 A

20 A

7 A

10 A

Irms​=2​I0​​=2​14A​≈10A

Q. An alternating current having peak value $14 A$ used to heat a metal wire. To produce the same heating effect, a constant current $i$ can be used where $i$ is

$I_{r m s} = \frac{I _{0}}{2} = \frac{14 A}{2} \approx 10 A$