An α - particle with a specific charge of 2.5× 107C kg-1 moves with a speed of 2× 105 ms-1 in a perpendicular magnetic field of 0.05 T . Then the radius of the circular path described by it is:

Question

An α - particle with a specific charge of 2.5× 107C kg-1 moves with a speed of 2× 105 ms-1 in a perpendicular magnetic field of 0.05 T . Then the radius of the circular path described by it is: (A) 8 cm (B) 4 cm (C) 16cm (D) 2cm

Tardigrade Admin · Accepted Answer

r=(mv/Bq) ⇒ r=(v/B(q)m)=(2× 105/0.005× 2.5× 107) =(2× 107/12.5× 107)=(200/12.5)cm=16 cm

Q. An $α -$ particle with a specific charge of $2.5 \times 10^{7} C k g^{- 1}$ moves with a speed of $2 \times 10^{5}$ $m s^{- 1}$ in a perpendicular magnetic field of $0.05 T$ . Then the radius of the circular path described by it is:

8 cm

4 cm

16cm

2cm

32 cm

$r = \frac{m v}{Bq}$
$\Rightarrow$ $r = \frac{v}{B \frac{q}{m}} = \frac{2 \times 10 ^{5}}{0.005 \times 2.5 \times 10 ^{7}}$
$= \frac{2 \times 10 ^{7}}{12.5 \times 10 ^{7}} = \frac{200}{12.5} c m = 16 c m$

Q. An α− particle with a specific charge of 2.5×107Ckg−1 moves with a speed of 2×105 ms−1 in a perpendicular magnetic field of 0.05T . Then the radius of the circular path described by it is: