An alloy of copper, silver and gold is found to have copper constituting the ccp lattice. If silver atoms occupy the edge centres and gold is present at body centre, the alloy has a formula

Question

An alloy of copper, silver and gold is found to have copper constituting the ccp lattice. If silver atoms occupy the edge centres and gold is present at body centre, the alloy has a formula (A) Cu Ag Au (B) Cu4Ag2Au (C) CuAg3 Au (D) Cu4Ag4Au

Tardigrade Admin · Accepted Answer

Number of Cu atoms at corners =8 × (1/8)=1 Number of Ag atoms at edge centers =12 × (1/4)=3 Number of Au atoms at body center =1 × 1=1 ∴ Formula is CuAg 3 Au.

Q. An alloy of copper, silver and gold is found to have copper constituting the ccp lattice. If silver atoms occupy the edge centres and gold is present at body centre, the alloy has a formula

$C u A g A u$

$C u_{4} A g_{2} A u$

$C u A g_{3} A u$

$C u_{4} A g_{4} A u$

Number of $C u$ atoms at corners $= 8 \times \frac{1}{8} = 1$
Number of $A g$ atoms at edge centers $= 12 \times \frac{1}{4} = 3$
Number of Au atoms at body center $= 1 \times 1 = 1$
$∴$ Formula is $C u A g_{3} A u$ .

Q. An alloy of copper, silver and gold is found to have copper constituting the ccp lattice. If silver atoms occupy the edge centres and gold is present at body centre, the alloy has a formula

CuAgAu

Cu4​Ag2​Au

CuAg3​Au

Cu4​Ag4​Au

Number of Cu atoms at corners =8×81​=1 Number of Ag atoms at edge centers =12×41​=3 Number of Au atoms at body center =1×1=1 ∴ Formula is CuAg3​Au.

$C u A g A u$

$C u_{4} A g_{2} A u$

$C u A g_{3} A u$

$C u_{4} A g_{4} A u$

Number of $C u$ atoms at corners $= 8 \times \frac{1}{8} = 1$
Number of $A g$ atoms at edge centers $= 12 \times \frac{1}{4} = 3$
Number of Au atoms at body center $= 1 \times 1 = 1$
$∴$ Formula is $C u A g_{3} A u$ .