An alkane of molecular weight 86 g/mol on monochlorination gives two products. The alkane is

Question

An alkane of molecular weight 86 g/mol on monochlorination gives two products. The alkane is (A) 2-Methylbutane (B) n-butane (C) 2, 2-Dimethyl propane (D) 2, 3-Dimethyl butane

Tardigrade Admin · Accepted Answer

CnH2 n + 2= 86 12n+ 2n+2=86 14n= 84 n=6 molecular formula =C6H14 for two monochloro products alkane must have 2-type H <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-4zvzku7w48qc.png" />

Q. An alkane of molecular weight 86 g/mol on monochlorination gives two products. The alkane is

2-Methylbutane

n-butane

2, 2-Dimethyl propane

2, 3-Dimethyl butane

$C_{n} H_{2 n + 2} = 86$

$12 n + 2 n + 2 = 86$

$14 n = 84$

$n = 6$

molecular formula $= C_{6} H_{14}$

for two monochloro products alkane must have 2-type H

Q. An alkane of molecular weight 86 g/mol on monochlorination gives two products. The alkane is

2-Methylbutane

n-butane

2, 2-Dimethyl propane

2, 3-Dimethyl butane

Cn​H2n+2​=86 12n+2n+2=86 14n=84 n=6 molecular formula =C6​H14​ for two monochloro products alkane must have 2-type H

$C_{n} H_{2 n + 2} = 86$

$12 n + 2 n + 2 = 86$

$14 n = 84$

$n = 6$

molecular formula $= C_{6} H_{14}$

for two monochloro products alkane must have 2-type H