An alkane (molecular weight =86 ) on monochlorination gives only two monochloro derivatives. One isomer (X) of this alkane is obtained in catalytic reduction of alkene (Y) which gives four monochloro derivatives. Isomer (X) is?

Question

An alkane (molecular weight =86 ) on monochlorination gives only two monochloro derivatives. One isomer (X) of this alkane is obtained in catalytic reduction of alkene (Y) which gives four monochloro derivatives. Isomer (X) is? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Alkene xrightarrow text catalytic reduction underbraceI+I I text isomers Mol. wt. =86 ⇒ C 6 H 14 Y (alkane) xrightarrow[ textreduction] text Catalytic X (isomer of A) xrightarrow text Monochlorination 4 monochloro derivatives. As X is isomer of A thus it should have molecular formula C 6 H 14 This isomer of hexane gives four monochloro products on chlorination.

Q. An alkane (molecular weight =86 ) on monochlorination gives only two monochloro derivatives. One isomer (X) of this alkane is obtained in catalytic reduction of alkene (Y) which gives four monochloro derivatives. Isomer (X) is?

Q. An alkane (molecular weight $= 86$ ) on monochlorination gives only two monochloro derivatives. One isomer $(X)$ of this alkane is obtained in catalytic reduction of alkene $(Y)$ which gives four monochloro derivatives. Isomer $(X)$ is?