An alcohol on treatment with alkaline KMnO4 gives a brown precipitate, the alcohol is

Question

An alcohol on treatment with alkaline KMnO4 gives a brown precipitate, the alcohol is (A)  (CH3)3COH  (B)  (C2H5)3COH  (C)  (C2H5)2C(CH3)OH  (D)  (CH3)3CCH2OH

Tardigrade Admin · Accepted Answer

During alkaline KMnO 4 oxidation brown precipitates of MnO 2 are formed. Out of the alcohols listed only ( CH 3)3 C - CH 2 OH is 1° alcohol and hence undergoes oxidation easily. All the remaining alcohols are 3° and hence, do not under go oxidation easily. 2 KMnO 4+ H 2 O arrow 2 MnO 2+2 KOH +3[ O ]

Q. An alcohol on treatment with alkaline $K M n O_{4}$ gives a brown precipitate, the alcohol is

$(C H_{3})_{3} CO H$

$(C_{2} H_{5})_{3} CO H$

$(C_{2} H_{5})_{2} C (C H_{3}) O H$

$(C H_{3})_{3} CC H_{2} O H$

Q. An alcohol on treatment with alkaline KMnO4​ gives a brown precipitate, the alcohol is

(CH3​)3​COH

(C2​H5​)3​COH

(C2​H5​)2​C(CH3​)OH

(CH3​)3​CCH2​OH

Q. An alcohol on treatment with alkaline $K M n O_{4}$ gives a brown precipitate, the alcohol is

$(C H_{3})_{3} CO H$

$(C_{2} H_{5})_{3} CO H$

$(C_{2} H_{5})_{2} C (C H_{3}) O H$

$(C H_{3})_{3} CC H_{2} O H$