An alcohol of formula C 9 H 12 O (A) reacts with Na 2 Cr 2 O 7 to form a compound having formula C 9 H 10 O. The original alcohol might be:

Question

An alcohol of formula C 9 H 12 O (A) reacts with Na 2 Cr 2 O 7 to form a compound having formula C 9 H 10 O. The original alcohol might be: (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

D U in A=4°, (benzene ring) DU in B =5° (benzene ring and

Hence (A) is 2°-alcohol.

Q. An alcohol of formula $C_{9} H_{12} O (A)$ reacts with $N a_{2} C r_{2} O_{7}$ to form a compound having formula $C_{9} H_{10} O$ . The original alcohol might be:

$D U$ in $A = 4^{\circ}$ , (benzene ring)
$D U$ in $B = 5^{\circ}$ (benzene ring and
Hence (A) is $2^{\circ}$ -alcohol.

Q. An alcohol of formula C9​H12​O(A) reacts with Na2​Cr2​O7​ to form a compound having formula C9​H10​O. The original alcohol might be:

DU in A=4∘, (benzene ring) DU in B=5∘ (benzene ring and Hence (A) is 2∘-alcohol.

Q. An alcohol of formula $C_{9} H_{12} O (A)$ reacts with $N a_{2} C r_{2} O_{7}$ to form a compound having formula $C_{9} H_{10} O$ . The original alcohol might be:

$D U$ in $A = 4^{\circ}$ , (benzene ring)
$D U$ in $B = 5^{\circ}$ (benzene ring and
Hence (A) is $2^{\circ}$ -alcohol.