An aircraft executes a horizontal loop with a speed of 150 m / s with its wings banked at an angle of 12°. The radius of the loop is: ( g =10 m / s 2)

Question

An aircraft executes a horizontal loop with a speed of 150 m / s with its wings banked at an angle of 12°. The radius of the loop is: ( g =10 m / s 2) (A) 10.6 km (B) 9.6 km (C) 7.4 km (D) 5.8 km

Tardigrade Admin · Accepted Answer

tan θ=(v2/r g) tan 12°=(150)2 / r × 10 ⇒ r=(2250/0.2125)=10.6 km

Q. An aircraft executes a horizontal loop with a speed of $150 m / s$ with its wings banked at an angle of $1 2^{\circ}$ . The radius of the loop is : $(g = 10 m / s^{2})$

$10.6 km$

$9.6 km$

$7.4 km$

$5.8 km$

$tan θ = \frac{v ^{2}}{r g}$
$tan 1 2^{\circ} = (150)^{2} / r \times 10$
$\Rightarrow r = \frac{2250}{0.2125} = 10.6 km$

Q. An aircraft executes a horizontal loop with a speed of 150m/s with its wings banked at an angle of 12∘. The radius of the loop is : (g=10m/s2)

10.6km

9.6km

7.4km

5.8km