An AC source is rated 222 V , 60 Hz. The average voltage is calculated in a time interval of 16.67 ms. It

Question

An AC source is rated 222 V , 60 Hz. The average voltage is calculated in a time interval of 16.67 ms. It (A) Must be zero (B) May be zero (C) Is never zero (D) Is (111 √2) V

Tardigrade Admin · Accepted Answer

T=(2 π/W)=(2 π/2 π(60))=16.67 ms ⇒ for time interval 16.67 ms (which is time period) average volatge will always be zero.

Q. An $A C$ source is rated $222 V, 60 Hz$ . The average voltage is calculated in a time interval of $16.67 m s$ . It

Must be zero

May be zero

Is never zero

Is $(1112) V$

$T = \frac{2 π}{W} = \frac{2 π}{2 π ( 60 )} = 16.67 m s$
$\Rightarrow$ for time interval $16.67 m s$ (which is time period) average volatge will always be zero.

Q. An AC source is rated 222V,60Hz. The average voltage is calculated in a time interval of 16.67ms. It