An AC current is given by I = I 1 sin ω t + I 2 cosω. A hot wire ammeter will give a reading :

Question

An AC current is given by I = I 1 sin ω t + I 2 cosω. A hot wire ammeter will give a reading : (A) √(I12-I22/2) (B) √( I 12+ I 22/2) (C) ( I 1+ I 2/√2) (D) ( I 1+ I 2/2 √2)

Tardigrade Admin · Accepted Answer

I = I 1 sin ω t + I 2 cos ω t ∴ I 0=√ I 12+ I 22 ∴ I rms =( I 0/√2)=√( I 12+ I 22/2)

Q. An AC current is given by $I = I_{1} sin ω t + I_{2}$ cos $ω$ . A hot wire ammeter will give a reading :

$\frac{I _{1}^{2} - I _{2}^{2}}{2}$

$\frac{I _{1}^{2} + I _{2}^{2}}{2}$

$\frac{I _{1} + I _{2}}{2}$

$\frac{I _{1} + I _{2}}{2 2}$

$I = I_{1} sin ω t + I_{2} cos ω t$
$∴ I_{0} = I_{1}^{2} + I_{2}^{2}$
$∴ I r m s = \frac{I _{0}}{2} = \frac{I _{1}^{2} + I _{2}^{2}}{2}$

Q. An AC current is given by I=I1​sinωt+I2​ cosω. A hot wire ammeter will give a reading :

2I12​−I22​​​

2I12​+I22​​​

2​I1​+I2​​

22​I1​+I2​​