Amplitude of the complex number i sin ( (π/19) ) is

Question

Amplitude of the complex number i sin ( (π/19) ) is (A)  (π/19) (B) - (π/19) (C)  (π/2) (D)  (π/2) - (π/19)

Tardigrade Admin · Accepted Answer

Let z = i sin (π/19) or z = 0 + i sin (π/19) Let amplitude of z be θ then sin θ =( sin (π/19)/√02+( sin (π )19)2) [ sin θ =(b/√a2+b2)] or sinθ =( sin (π /19)/ sin (π )19) =1 ⇒ θ =(π/2)

Q. Amplitude of the complex number $i sin (\frac{π}{19})$ is

$\frac{π}{19}$

$- \frac{π}{19}$

$\frac{π}{2}$

$\frac{π}{2} - \frac{π}{19}$

Q. Amplitude of the complex number isin(19π​) is

19π​

−19π​

2π​

2π​−19π​

Let z=isin19π​ or z=0+isin19π​ Let amplitude of z be θ then sinθ=02+(sin19π​)2​sin19π​​[sinθ=a2+b2​b​] or sinθ=sin19π​sin19π​​=1⇒θ=2π​

Q. Amplitude of the complex number $i sin (\frac{π}{19})$ is

$\frac{π}{19}$

$- \frac{π}{19}$

$\frac{π}{2}$

$\frac{π}{2} - \frac{π}{19}$