Question

Among the interhalide species
$I{F}_2^{\ominus },I{F}_3,I{F}_4^{\ominus }$, and $I{F}_7$

• A. All iodine centers are either $s{p}^{3}d$ or $s{p}^3{d}^2$ hybridized
• B. The minimum angular separation between fluorine atoms is $60^{\circ }$
• C. The anionic species are both isoelectronic and isostructural to $Xe{F}_2$ and $Xe{F}_4$
• D. There is no species having a single lone pair of electrons

Answer 1

Answer: (C)

Hybridization and structure of $I{F}_2^{-}\to sp{}^{3}d$ and linear Hybridization and structure of $Xe{F}_2\to s{p}^{3}d$ and linear
So Both $Xe{F}_2$ and $I{F}_2^{-}$are isostructural and isoelectronic Hybridization and structure of $I{F}_4^{-}\to s{p}^3{d}^2$ and square planar Hybridization and structure of $Xe{F}_4\to s{p}^3{d}^2$ and square planar Hence, both $Xe{F}_4$ and $I{F}_4^{-}$are isoelectronic and isostructural.