Question

Among $\left[Ni{\left(CO\right)}_4\right]{\left[NiC{l}_4\right]}^{2-}\left[Co{\left(N{H}_3\right)}_{4}C{l}_2\right]Cl,N{a}_3\left[Co{F}_6\right],N{a}_2{O}_2$ and $Cs{O}_2$ find the total number of paramagnetic compounds.

Answer 1

Answer: 3

Compound/Ion	Magnetic nature of compound
$\left[Ni{\left(CO\right)}_4\right]$	Diamagnetic
${\left[NiC{l}_2\right]}^{2-}$	Paramagnetic
$\left[Co{\left(N{H}_3\right)}_{4}C{l}_2\right]Cl$	Diamagnetic
$N{a}_3\left[Co{F}_6\right]$	Paramagnetic
$N{a}_2{O}_2$	Diamagnetic
$Cs{O}_2$	Paramagnetic

So total number of paramagnetic compounds is 3.