Ammonium carbonate dissociates as NH 2 COONH 4( s ) leftharpoons 2 NH 3( g )+ CO 2( g ) In a closed vessel having ammonium carbonate in equilibrium, NH3 is added such that partial pressure of NH3 now, is equals to the original total pressure. The ratio of total pressure now and the original pressure is?

Question

Ammonium carbonate dissociates as NH 2 COONH 4( s ) leftharpoons 2 NH 3( g )+ CO 2( g ) In a closed vessel having ammonium carbonate in equilibrium, NH3 is added such that partial pressure of NH3 now, is equals to the original total pressure. The ratio of total pressure now and the original pressure is? (A) (27/31) (B) (31/27) (C) (4/9) (D) (31/9)

Tardigrade Admin · Accepted Answer

NH 2 COONH 4( s ) leftharpoons 2 NH 3( g )+ CO 2( g ) Suppose P is pressure of CO 2 at equilibrium than beginarrayl P NH 3=2 P P text Total =2 P + P =3 P text As K P =( P NH 3)2( P CO 2)=4 P 3 endarray On adding NH 3 at equilibrium P NH 3= P text Total =3 P So K P =4 P 3=( P NH 3)2 ⋅( P prime CO 2) 4 P 3=(3 P )2( P prime CO 2) P prime CO 2=(4/9) P Now total P prime=3 P +(4/9) P =(31/9) P Hence pressure ratio ((P prime/ P ))=((31/9) P /3 P ) =(31/27)

$\frac{27}{31}$

$\frac{31}{27}$

$\frac{4}{9}$

$\frac{31}{9}$

3127​

2731​

94​

931​

$\frac{27}{31}$

$\frac{31}{27}$

$\frac{4}{9}$

$\frac{31}{9}$