α-particles are projected towards the nuclei of the different metals, with the same kinetic energy. The distance of closest approach is minimum for

Question

α-particles are projected towards the nuclei of the different metals, with the same kinetic energy. The distance of closest approach is minimum for (A) Cu(Z=29) (B) Ag(Z=47) (C) Au(Z=79) (D) pd(Z=46)

Tardigrade Admin · Accepted Answer

r= (1/4 π ε0) (q1 q2/(KE)) ⇒ r α q2

Q. $α$ -particles are projected towards the nuclei of the different metals, with the same kinetic energy. The distance of closest approach is minimum for

Cu(Z=29)

Ag(Z=47)

Au(Z=79)

pd(Z=46)

$r = \frac{1}{4 π ε _{0}} \frac{q _{1} q _{2}}{( K E )} \Rightarrow r α q_{2}$

Q. α-particles are projected towards the nuclei of the different metals, with the same kinetic energy. The distance of closest approach is minimum for