Allylic halogen substitution can be done with

Question

Allylic halogen substitution can be done with (A) halogen at high temperature (B) NBS in sunlight (C) sulphonyl chloride in sunlight (D) all of these.

Tardigrade Admin · Accepted Answer

CH 2= CH - CH 3+ Cl 2 xrightarrow600 K CH 2= CH - CH 2- Cl + HCl <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/af511c35865637401d17589a7e034500-.png" /> CH 2= CH - CH 3+ SO 2 Cl 2 xrightarrowhv CH 2= CH - CH 2- Cl +SO 2+ HCl

Q. Allylic halogen substitution can be done with

halogen at high temperature

NBS in sunlight

sulphonyl chloride in sunlight

all of these.

$C H_{2} = C H - C H_{3} + C l_{2} 600 K C H_{2} = C H - C H_{2} - Cl + H Cl$

$C H_{2} = C H - C H_{3} + S O_{2} C l_{2} h v C H_{2} = C H - C H_{2} - Cl + S O_{2} + H Cl$

Q. Allylic halogen substitution can be done with

halogen at high temperature

NBS in sunlight

sulphonyl chloride in sunlight

all of these.

CH2​=CH−CH3​+Cl2​600K​CH2​=CH−CH2​−Cl+HCl CH2​=CH−CH3​+SO2​Cl2​hv​CH2​=CH−CH2​−Cl+SO2​+HCl

$C H_{2} = C H - C H_{3} + C l_{2} 600 K C H_{2} = C H - C H_{2} - Cl + H Cl$

$C H_{2} = C H - C H_{3} + S O_{2} C l_{2} h v C H_{2} = C H - C H_{2} - Cl + S O_{2} + H Cl$